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Home » News » industry information » How to realize the supercapacitor fully depleted power (II)

How to realize the supercapacitor fully depleted power (II)

Views: 7     Author: Site Editor     Publish Time: 2018-05-23      Origin: Site

But if the super capacitor is only discharged to 2.5V, when the system closes, it will leave quite a lot of electricity in the super capacitor. The electrical energy stored in supercapacitors is equal to CV2. For example, the 1F super capacitor is charged to 5V through your input power, so that the energy absorbed from the capacitor is only 9.4J when it is discharged to 2.5V only. But if the supercapacitor just mentioned a power supply to the system to reduce its voltage to 0.7V, the electric energy derived from the capacitor is about 12.2J - more than 30% of the electric energy is absorbed.

 

The TI Designs reference design with a low input voltage and large current boost converter with TPS61088 shows a simple design that can draw more power from a supercapacitor or other very low input voltage sources, such as a single alkaline battery or a nickel battery. The high power TPS61088 stepper converter can accomplish the task of converting the electrical energy of super capacitor to the voltage rail of the system. The minitype low power TLV61220 step down converter can provide bias voltage for TPS61088 power supply. This small low-cost additional circuit is the key to extracting almost all electrical energy from your super capacitor.


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